How To Calculate The Bar Bending Schedule For Combined Foundation
Bar bending schedule or BBS for any foundation means calculation the rebar details using in the foundation. also calculate the weight of the steel diameter of the steel fixing location of the steel, spacing between two bar and also the length of the bar. Calculate The Bar Bending Schedule For Combined Foundation
In This article I will explain the bar bending schedule for combined foundation. we calculate the bar bending schedule with the help of given data. The given data is mention in the drawing.
How To Calculate The Bar Bending Schedule For Combined Foundation
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Given Data
length of the combined footing = 3500mm
width of the combined footing = 2000mm
Height of the footing = 450mm
Height of the column without footing = 925mm
Height of the column with footing = 1375mm
Diameter of the footing bar = 16mm
Diameter of the vertical bar = 16mm
Diameter of the inner Rings = 10mm
Spacing between two bar in footing bar = 150mm
Spacing between two bar in Column bar = 150mm
Concrete cover for footing and column = 50mm
Number of bar in column = 12 No’s
Solution
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Length of the Footing bar
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Weight of the Footing bar
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Length of the Vertical bar
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Weight of the Vertical bar
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Length of the Outer Ring
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Length of the Inner Ring
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Weight of the Outer and Inner Ring
1- Length of the Footing Bar
Cutting length of the Footing Bar (B)
Cutting Length long bar = length of the footing – 2 C.C + 2 hooks (90 degree)
Hooks (90º)= Footing height -2 C.C – Diameter of bar = 450-100 -16=334mm
Cutting Length of long bar (B)= 3500 – 2(50) + 2(334) = 2732mm
Number of Long Bar (B)
Number of long bar (B) = Total width – 2 C.C / Spacing +1
Number of long bar (B) = 2000 – 2(50) / 150 + 1 = 14 No’s
Total length of long bar (B) = Number of bar x length of one bar
Total length of long bar (B) = 14 x 2732 = 38248mm
Cutting length of the Footing Bar (T)
Cutting Length of long bar (T) = 3500 – 2(50) + 2(334) = 2732mm
Number of Long Bar (T)
Number of long bar (T) = Total width – 2 C.C / Spacing +1
Number of long bar (T) = 2000 – 2(50) / 150 + 1 = 14 No’s
Total length of long bar (T) = Number of bar x length of one bar
Total length of long bar (T) = 14 x 2732 = 38248mm
Total length B and T bar =38248 + 38248 =76.496m
Cutting length of short bar
Cutting length of short bar(B) =Width of footing – 2 C.C + 2 hooks (90º)
Hooks (90º)= Footing height -2 C.C – Diameter of bar = 450-100 -16=334mm
Cutting length of short bar (B) = 2000 – 2 (50) + 2(334) = 1232mm
Number of the short bar (B)
Number of the short bar = Total length of footing – 2 C.C /Spacing +1
Number of the short bar = 3500 – 100 /150 + 1 = 24No’s
Total length of short bar = Number of short bar x cutting length of one bar
Total length of short bar = 24 x 1232 =29.568m
The cutting length of short bar bottom and short bar top is same length and number
Total length of short bar bottom and top short bar is same
Total length of short bar bottom and top short bar = 29.568 + 29.568 = 59.136m
Total length bottom and top bar = 76.496 + 59.136 = 135.632m
2-Weight of the Footing
Weight of the Footing Bar = d²/162 x Total length
Weight of the Footing Bar = 16² / 162 x 135.632 = 214.33kG = 215KG
3- Length of vertical bar
Cutting Length of vertical bar = Total height of foundation – 2 C.C +bottom hook(20D) + top hook(34D)
Cutting Length of vertical bar = 1375 – 100 + 320 + 544 = 2139mm
Number of bars = 12 No’s
Total length of vertical bar = Number of bar x Cutting length of one bar
Total length of Vertical bar = 12 x 2139 = 25.668m
4-Weight of vertical bar
Weight of Vertical bar = d² / 162 x total length
Weight of Vertical bar 16² / 162 x 25.668 = 40.56KG = 41KG
5- Length of Outer Ring
Cutting length of the inner ring = 2(length of column + Breath of column -4 C.C)+2 hooks(10d)
Cutting length of the outer ring = 2[(650 + 650-4(50)]+ 2(100) =2400mm
Number of outer Ring
Number of outer Ring = Height of the column – CC / spacing +1
Number of outer Ring = 975 -50 /150 +1 =8 No’s
Total length = Number of ring x cutting length
Total length = 8 x 2400 =19.200m
6-Length of Inner Ring
Cutting length of inner ring = 2 x length of column – 2CC /3 +2 x width of column- 2C.C +2Hooks(10d)
Cutting length of inner ring =2 (650-100)/3 +2(650-100) + 2 (10×10)
Cutting length of inner ring = 1100/3 + 1100 + 200
Cutting length of inner ring = 367+1100+200= 1667mm
Number of inner ring
Number of inner ring and number of outer ring is same
Number of inner ring = 8 = 8
Inner side two ring so
Number of inner ring = 16 No’s
Total length of both inner Ring = Number of inner ring x cutting length of one inner ring
Total length of both inner Ring = 16 x 1667 =26.672m
Total length of outer and inner ring = 19.200 + 26.672 = 45.872m
7- Weight of Outer Ring And Inner Ring
Weight of Outer Ring And Inner Ring = d² / 162 x Total length
Weight of Outer Ring And Inner Ring = 10² / 162 X 45.872 = 29KG
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